b^2-6b=22

Solution for b^2-6b=22 equation:

b^2-6b=22

We move all terms to the left:

b^2-6b-(22)=0

a = 1; b = -6; c = -22;
Δ = b2-4ac
Δ = -62-4·1·(-22)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{31}}{2*1}=\frac{6-2\sqrt{31}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{31}}{2*1}=\frac{6+2\sqrt{31}}{2}
$